SNVSAC1 June 2015 LMR16006Y-Q1
PRODUCTION DATA.
NOTE
Information in the following applications sections is not part of the TI component specification, and TI does not warrant its accuracy or completeness. TI’s customers are responsible for determining suitability of components for their purposes. Customers should validate and test their design implementation to confirm system functionality.
The LMR16006Y-Q1 is a step down DC-to-DC regulator. It is typically used to convert a higher DC voltage to a lower DC voltage with a maximum output current of 600 mA. Detailed Design Procedure can be used to select components for the LMR16006Y-Q1.
Figure 7 shows typical application where user can adjust output by R1 and R2.
Example requirements for typical buck regulators with high-efficiency applications:
DESIGN PARAMETER | EXAMPLE VALUE | |
---|---|---|
Input voltage, VIN | 9 V to 16 V, typical 12 V | |
Output voltage, VOUT | 5 V ± 3% | |
Maximum output current IO_max | 0.6 A | |
Minimum output current IO_min | 0.03 A | |
Transient response 0.03 A to 0.6 A | 5% | |
Output voltage ripple | 1% | |
Switching frequency ƒSW | 2.1 MHz | |
Target during Load Transient | Overvoltage peak value | 106% of output voltage |
Undervoltage value | 91% of output voltage |
This example details the design of a high frequency switching regulator using ceramic output capacitors. A few parameters must be known in order to start the design process. These parameters are typically determined at the system level:
The most critical parameters for the inductor are the inductance, peak current and the DC resistance. The inductance is related to the peak-to-peak inductor ripple current, the input and the output voltages. Since the ripple current increases with the input voltage, the maximum input voltage is always used to determine the inductance. To calculate the minimum value of the output inductor, use Equation 1. KIND is a coefficient that represents the amount of inductor ripple current relative to the maximum output current. A reasonable value is setting the ripple current to be 30%-40% of the DC output current. For this design example, the minimum inductor value is calculated to be 6.82 µH, and a nearest standard value was chosen: 6.8 µH. For the output filter inductor, it is important that the RMS current and saturation current ratings not be exceeded. The RMS and peak inductor current can be found from Equation 3 and Equation 4. The inductor ripple current is 0.074 A, and the RMS current is 0.60 A. As the equation set demonstrates, lower ripple currents will reduce the output voltage ripple of the regulator but will require a larger value of inductance. A good starting point for most applications is 6.8 μH with a 1.6 A current rating. Using a rating near 1.6 A will enable the LMR16006Y-Q1 to current limit without saturating the inductor. This is preferable to the LMR16006Y-Q1 going into thermal shutdown mode and the possibility of damaging the inductor if the output is shorted to ground or other long-term overload.
The selection of Cout is mainly driven by three primary considerations. The output capacitor will determine the modulator pole, the output voltage ripple, and how the regulator responds to a large change in load current. The output capacitance needs to be selected based on the most stringent of these three criteria.
The desired response to a large change in the load current is the first criteria. The regulator usually needs two or more clock cycles for the control loop to see the change in load current and output voltage and adjust the duty cycle to react to the change. The output capacitance must be large enough to supply the difference in current for 2 clock cycles while only allowing a tolerable amount of droop in the output voltage. Equation 5 shows the minimum output capacitance necessary to accomplish this. The transient load response is specified as a 3% change in VOUT for a load step from 0.03 A to 0.6 A (full load), ΔIOUT = 0.6 – 0.03 = 0.57 A and ΔVOUT = 0.03 × 5 = 0.15 V. Using these numbers gives a minimum capacitance of 3.62 µF. For ceramic capacitors, the ESR is usually small enough to ignore in this calculation. Aluminum electrolytic and tantalum capacitors have higher ESR that should be taken into account.
The stored energy in the inductor will produce an output voltage overshoot when the load current rapidly decreases. The output capacitor must also be sized to absorb energy stored in the inductor when transitioning from a high load current to a lower load current. Equation 6 is used to calculate the minimum capacitance to keep the output voltage overshoot to a desired value. Where L is the value of the inductor, IOH is the output current under heavy load, IOL is the output under light load, Vf is the final peak output voltage, and Vi is the initial capacitor voltage. For this example, the worst case load step will be from 0.6 A to 0.03 A. The output voltage will increase during this load transition and the stated maximum in our specification is 3% of the output voltage. This will make Vo_overshoot = 1.03 × 5 = 5.15 V. Vi is the initial capacitor voltage which is the nominal output voltage of 5 V. Using these numbers in Equation 6 yields a minimum capacitance of 1.6 µF.
Equation 7 calculates the minimum output capacitance needed to meet the output voltage ripple specification. Where ƒsw is the switching frequency, Vo_ripple is the maximum allowable output voltage ripple, and IL_ripple is the inductor ripple current. Equation 7 yields 95 nF.
Equation 8 calculates the maximum ESR an output capacitor can have to meet the output voltage ripple specification. Equation 8 indicates the ESR should be less than 623 mΩ.
Additional capacitance de-ratings for aging, temperature and dc bias should be factored in which will increase this minimum value. For this example, 10 µF ceramic capacitors will be used. Capacitors in the range of 4.7 µF-100 µF are a good starting point with an ESR of 0.7 Ω or less.
The breakdown voltage rating of the diode is preferred to be 25% higher than the maximum input voltage. In the target application, the current rating for the diode should be equal or greater to the maximum output current for best reliability in most applications. In cases where the input voltage is not much greater than the output voltage the average diode current is lower. In this case it is possible to use a diode with a lower average current rating, approximately (1-D) × IOUT. However the peak current rating should be higher than the maximum load current. A 0.5 A to 1 A rated diode is a good starting point.
A low ESR ceramic capacitor is needed between the VIN pin and ground pin. This capacitor prevents large switching voltage transients from appearing at the input. Use a 1 µF-10 µF value with X5R or X7R dielectric. Depending on construction, a ceramic capacitor’s value can decrease up to 50% of its nominal value when rated voltage is applied. Consult with the capacitor manufactures data sheet for information on capacitor derating over voltage and temperature. The capacitor must also have a ripple current rating greater than the maximum input current ripple of the LMR16006Y-Q1. The input ripple current can be calculated using below Equation 9.
For this example design, one 2.2 µF, 50 V capacitor is selected. The input capacitance value determines the input ripple voltage of the regulator. The input voltage ripple can be calculated using Equation 10. Using the design example values, IOUT_max = 0.6 A, Cin = 2.2 µF, ƒSW = 2100 kHz, yields an input voltage ripple of 33 mV and a rms input ripple current of 0.3 A.
A 0.1 μF ceramic capacitor or larger is recommended for the bootstrap capacitor (CBOOT). For applications where the input voltage is close to output voltage a larger capacitor is recommended, generally 0.1 µF to 1 µF to ensure plenty of gate drive for the internal switches and a consistently low RDSON. A ceramic capacitor with an X7R or X5R grade dielectric with a voltage rating of 10 V or higher is recommended because of the stable characteristics over temperature and voltage.
Unless otherwise specified the following conditions apply: VIN = 12 V, ƒSW = 2100 kHz, L1 = 6.8 µH, COUT = 10 µF, TA = 25°C.
VOUT = 5 V | IOUT = 0 mA |
VIN = 15 V | VOUT = 12 V | IOUT = 600 mA |
VIN = 12 V | VOUT = 5 V | IOUT = 600 mA |
VOUT = 5 V | IOUT = 600 mA |
VIN = 15 V | VOUT = 12 V | IOUT = 600 mA |
VIN = 12 V | VOUT = 5 V |
Figure 14 shows the typical application circuit with a fixed output.