SNVSBK2A September 2019 – June 2021 LP8733
PRODUCTION DATA
The inductor current ripple can be calculated using Equation 1 and Equation 2:
Example using Equation 1 and Equation 2:
VIN(max) = 5.5 V |
VOUT = 1 V |
η = 0.75 |
fSW = 1.8 MHz |
L = 0.38 µH |
then D = 0.242 and ΔIL = 1.59 A |
Peak current is half of the current ripple. If ILIM_FWD_SET_OTP is 3 A, the minimum forward current limit would be 2.85 A when taking the –5% tolerance into account. In this case the difference between set peak current and maximum load current = 0.795 A + 0.15 A = 0.945 A.