JAJSF48 March 2018 LP87561-Q1 , LP87562-Q1 , LP87563-Q1 , LP87564-Q1 , LP87565-Q1
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The worst case inductor current ripple can be calculated using Equation 1 and Equation 2:
Example using Equation 1 and Equation 2:
VIN(max) = 5.5 V |
VOUT(max) = 1 V |
η(min) = 0.75 |
fSW(min) = 1.8 MHz |
L(min) = 0.38 µH |
then D(max) = 0.242 and ΔIL(max) = 1.59 A |
Peak current is half of the current ripple. If ILIM_FWD_SET_OTP is 5 A, the minimum forward current limit would be 4.75 A when taking the –5% tolerance into account. In the worst case situation difference between set peak current and maximum load current = 0.795 A + 0.25 A = 1.045 A.