SLAS629B March 2009 – May 2020 MSP430F477 , MSP430F478 , MSP430F479
PRODUCTION DATA.
PARAMETER | TEST CONDITION | MIN | TYP | MAX | UNIT | |||
---|---|---|---|---|---|---|---|---|
I(AM) | Active mode(1)
f(MCLK) = f(SMCLK) = 1 MHz, f(ACLK) = 32768 Hz, XTS = 0, SELM = 0 or 1 |
TA = –40°C to 85°C | VCC = 2.2 V | 262 | 295 | µA | ||
VCC = 3 V | 420 | 460 | ||||||
I(LPM0) | Low power mode (LPM0)(1) | TA = –40°C to 85°C | VCC = 2.2 V | 32 | 62 | µA | ||
VCC = 3 V | 51 | 77 | ||||||
I(LPM2) | Low-power mode (LPM2),
f(MCLK) = f(SMCLK) = 0 MHz, f(ACLK) = 32768 Hz, SCG0 = 0(2) |
TA = –40°C to 85°C | VCC = 2.2 V | 5 | 9 | µA | ||
VCC = 3 V | 7 | 13 | ||||||
I(LPM3) | Low-power mode (LPM3),
f(MCLK) = f(SMCLK) = 0 MHz, f(ACLK) = 32768 Hz, SCG0 = 1, Basic Timer1 enabled, ACLK selected, LCD_A enabled, LCDCPEN = 0, (static mode, fLCD = f(ACLK)/32)(2)(3) |
TA = –40°C | VCC = 2.2 V | 1.0 | 1.8 | µA | ||
TA = 25°C | 1.0 | 1.8 | ||||||
TA = 60°C | 1.1 | 2.0 | ||||||
TA = 85°C | 2.3 | 4.0 | ||||||
TA = –40°C | VCC = 3 V | 1.2 | 2.0 | |||||
TA = 25°C | 1.2 | 2.0 | ||||||
TA = 60°C | 1.4 | 2.2 | ||||||
TA = 85°C | 2.7 | 4.5 | ||||||
I(LPM3) | Low-power mode (LPM3),
f(MCLK) = f(SMCLK) = 0 MHz, f(ACLK) = 32768 Hz, SCG0 = 1, Basic Timer1 enabled, ACLK selected, LCD_A enabled, LCDCPEN = 0, (4-mux mode; fLCD = f(ACLK)/32)(2)(3) |
TA = –40°C | VCC = 2.2 V | 1.0 | 3.0 | µA | ||
TA = 25°C | 1.1 | 3.2 | ||||||
TA = 85°C | 3.5 | 6.0 | ||||||
TA = –40°C | VCC = 3 V | 1.8 | 3.3 | |||||
TA = 25°C | 2.0 | 4.0 | ||||||
TA = 85°C | 4.2 | 7.5 | ||||||
I(LPM4) | Low-power mode (LPM4),
f(MCLK) = 0 MHz, f(SMCLK) = 0 MHz, f(ACLK) = 0 Hz, SCG0 = 1(2) |
TA = –40°C | VCC = 2.2 V | 0.1 | 0.5 | µA | ||
TA = 25°C | 0.1 | 0.5 | ||||||
TA = 60°C | 0.7 | 1.1 | ||||||
TA = 85°C | 1.7 | 3.0 | ||||||
TA = –40°C | VCC = 3 V | 0.1 | 0.8 | |||||
TA = 25°C | 0.1 | 0.8 | ||||||
TA = 60°C | 0.8 | 1.2 | ||||||
TA = 85°C | 1.5 | 3.5 |
Current consumption of active mode versus system frequency:
I(AM) = I(AM) [1 MHz] × f(System) [MHz]
Current consumption of active mode versus supply voltage:
I(AM) = I(AM) [3 V] + 200 µA/V × (VCC – 2.2 V)