JAJSPL2 October 2024 TPSM82916
ADVANCE INFORMATION
Using a ferrite bead for the second stage L-C filter minimizes the external component count because most of the noise sensitive circuits use a RF bead for high frequency attenuation as a default component at the inputs.
Make sure to select a ferrite bead with sufficiently high inductance at full load, and with low DC resistance (below 10mΩ) to keep the module efficiency as high as possible. The ferrite bead inductance decreases with increased load current. Therefore, the ferrite bead must have a current rating much higher than the desired load current.
The recommendation is to choose a ferrite bead with an impedance of 8Ω to 20Ω at 100MHz. Ferrite beads can be used in parallel if higher current is needed, however this can halve the inductance and filtering. Refer to Table 7-5 for possible ferrite beads.
PART NUMBER | MANUFACTURER | SIZE | IMPEDANCE AT 100MHZ | INDUCTANCE AT 100MHz (CALCULATED) | DC RESISTANCE | CURRENT RATING |
---|---|---|---|---|---|---|
BLE18PS080SN1 | MuRata | 0603 | 8.5Ω | 13.5 nH | 4mΩ | 5A |
BLE32SN120SN1L | MuRata | 1210 | 12Ω | 18 nH | 0.78mΩ | 20A |
74279221100 | Wurth Elektronik | 1206 | 10Ω | 15.9 nH | 3mΩ | 10.5A |
7427922808 | Wurth Electronik | 0603 | 8Ω | 12.7 nH | 5mΩ | 9.5A |
The internal compensation has been designed to be stable with up to 50nH of inductance in the second stage filter. To achieve low ripple, the second L-C filter requires only 5nH to 10nH inductance. The inductance can be estimated from the ferrite bead impedance specification at 100MHz, with the assumption that the inductance is similar at the selected module switching frequency of 1MHz, 1.4MHz, or 2.2MHz, and can be verified through tools available on some manufacturer websites. Use Equation 5 to calculate the inductance of a ferrite bead:
where