SBOK086 December   2024 TRF0208-SEP

 

  1.   1
  2.   2
  3.   Trademarks
  4. Overview
  5. Single-Event Effects
  6. Test Device and Evaluation Board Information
  7. Irradiation Facility and Setup
  8. Depth, Range, and LETEFF Calculation
  9. Test Set-Up and Procedures
  10. Single-Event Latch-up (SEL) Results
  11. Single-Event Transients (SET) Results
  12. Event Rate Calculations
  13. 10Summary
  14.   A Total Ionizing Dose from SEE Experiments
  15.   B Confidence Interval Calculations
  16.   C References

Confidence Interval Calculations

For conventional products where hundreds of failures are seen during a single exposure, one can determine the average failure rate of parts being tested in a heavy-ion beam as a function of fluence with high degree of certainty and reasonably tight standard deviation, and thus have a good deal of confidence that the calculated cross-section is accurate.

With radiation hardened parts however, determining the cross-section becomes more difficult since often few, or even, no failures are observed during an entire exposure. Determining the cross-section using an average failure rate with standard deviation is no longer a viable option, and the common practice of assuming a single error occurred at the conclusion of a null-result can end up in a greatly underestimated cross-section.

In cases where observed failures are rare or non-existent, the use of confidence intervals and the chi-squared distribution is indicated. The Chi-Squared distribution is particularly good for the determination of a reliability level when the failures occur at a constant rate. In the case of SEE testing, where the ion events are random in time and position within the irradiation area, one expects a failure rate that is independent of time (presuming that parametric shifts induced by the total ionizing dose do not affect the failure rate), and thus the use of chi-squared statistical techniques is valid (since events are rare an exponential or Poisson distribution is usually used).

In a typical SEE experiment, the device-under-test (DUT) is exposed to a known, fixed fluence (ions/cm2) while the DUT is monitored for failures. This is analogous to fixed-time reliability testing and, more specifically, time-terminated testing, where the reliability test is terminated after a fixed amount of time whether or not a failure has occurred (in the case of SEE tests fluence is substituted for time and hence this is a fixed fluence test) [5]. Calculating a confidence interval specifically provides a range of values which is likely to contain the parameter of interest (the actual number of failures/fluence). Confidence intervals are constructed at a specific confidence level. For example, a 95% confidence level implies that if a given number of units were sampled numerous times and a confidence interval estimated for each test, the resulting set of confidence intervals brackets the true population parameter in about 95% of the cases.

To estimate the cross-section from a null-result (no fails observed for a given fluence) with a confidence interval, we start with the standard reliability determination of lower-bound (minimum) mean-time-to-failure for fixed-time testing (an exponential distribution is assumed):

Equation 2. M T T F = 2 n T χ 2 ( d + 1 ) ; 100 ( 1 - α 2 ) 2

Where MTTF is the minimum (lower-bound) mean-time-to-failure, n is the number of units tested (presuming each unit is tested under identical conditions) and T, is the test time, and x2 is the chi-square distribution evaluated at 100 (1 – σ / 2) confidence level and where d is the degrees-of-freedom (the number of failures observed). With slight modification for our purposes we invert the inequality and substitute F (fluence) in the place of T:

Equation 3. M F T F = 2 n F χ 2 ( d + 1 ) ; 100 ( 1 - α 2 ) 2

Where now MFTF is mean-fluence-to-failure and F is the test fluence, and as before, x2 is the chi-square distribution evaluated at 100 (1 – σ / 2) confidence and where d is the degrees-of-freedom (the number of failures observed). The inverse relation between MTTF and failure rate is mirrored with the MFTF. Thus the upper-bound cross-section is obtained by inverting the MFTF:

Equation 4. σ = χ 2 ( d + 1 ) ; 100 ( 1 - α 2 ) 2 2 n F

Let’s assume that all tests are terminated at a total fluence of 106 ions/cm2. Let’s also assume that we have a number of devices with very different performances that are tested under identical conditions. Assume a 95% confidence level (σ = 0.05). Note that as d increases from 0 events to 100 events the actual confidence interval becomes smaller, indicating that the range of values of the true value of the population parameter (in this case the cross-section) is approaching the mean value + 1 standard deviation. This makes sense when one considers that as more events are observed the statistics are improved such that uncertainty in the actual device performance is reduced.

Table B-1 Experimental Example Calculation of Mean-Fluence-to-Failure (MFTF) and σ Using a 95% Confidence Interval
Degrees-of-Freedom (d)2(d + 1)χ2 at 95%Calculated Cross-Section (cm2)
Upper-Bound at 95% ConfidenceMeanAverage + Standard Deviation
027.383.69E–060.00E+000.00E+00
1411.145.57E–061.00E–062.00E–06
2614.457.22E–062.00E–063.41E–06
3817.538.77E–063.00E–064.73E–06
41020.481.02E–054.00E–066.00E–06
51223.341.17E–055.00E–067.24E–06
102236.781.84E–051.00E–051.32E–05
50102131.846.59E–055.00E–055.71E–05
100202243.251.22E–041.00E–041.10E–04