SLVSHL9 November 2024 TPS922051
PRODUCTION DATA
For this design, the input voltage is a 24V rail with 10% variation. The output is 4 white LEDs in series and the inductor current ripple by requirement is less than 30% of maximum inductor current. To choose a proper peak-to-peak inductor current ripple, the low-side FET current limit should not be violated when the converter works in full-load condition. This requires half of the peak-to-peak inductor current ripple to be lower than that limit. Another consideration is to ensure reasonable inductor core loss and copper loss caused by the peak-to-peak current ripple. Once this peak-to-peak inductor current ripple is chosen, use the equation below to calculate the recommended value of the output inductor L.
where
With the chosen inductor value, the user can calculate the actual inductor current ripple using the equation below.
The ratings of inductor RMS current and saturation current must be greater than those seen in the system requirement. This is to ensure no inductor overheat or saturation occurring. During power up, transient conditions or fault conditions, the inductor current may exceed its normal operating current and reach the current limit. Therefore, it is preferred to select a saturation current rating equal to or greater than the converter current limit. The peak-inductor-current and RMS current equations are shown in the equations below .
In this design, VIN(max) = 24V, VOUT = 12V, ILED = 2A, fSW = 400kHz, choose KIND = 0.3, the calculated inductance is 25µH. A 33µH inductor is chosen. With this inductor, the ripple, peak, and rms currents of the inductor are 0.45A, 2.2A, and 2.01A, respectively.