TIDT247 February   2022

 

  1.   Description
  2. 1Board Connections, Jumpers, and Test Points
  3. 2Pin Functions
  4. 3Quick Start Guide
  5. 4Testing and Results
    1. 4.1 Thermal Image
    2. 4.2 Control Loop
    3. 4.3 Efficiency - Output Voltage 8.5 V
  6. 5Waveforms

Quick Start Guide

CAUTION: Manual control of the two power inputs is possible when removing the jumper from J16, but precautions must be taken to not switch to the secondary power input while the input capacitor of the boost converter is charged to a voltage above 5 V. This will cause a voltage spike at the battery terminals which can potentially damage the fuel gauge IC.

The switchover also occurs when the ideal diode is disabled by asserting the control input low.

The input voltage of the boost converter can be measured at TP10.

When powering down the board, remove the 12-V input first.

Power up the board:

  1. Ensure J16 is shorted.
  2. Connect the PMP30963 board to the EV2400 via J2. Ensure 3.3 V are applied to pin 4 of J2.
  3. Connect any of the voltage outputs from the EV2400 to J5, pin 6. This pin is used to control the learning load and the EV2400 utilizes the voltage outputs as a control signal.
  4. Connect a Li battery to J1/J3. The battery and its connection must be low impedance.
  5. Connect a 12-V supply to J10/J14. Ensure that this source is low impedance.
  6. Provide the necessary control signals to the following pins of J5: pin 2 (charger enable), pin 12 (booster enable), pin 18 (ideal diode enable).

When all voltages are applied, the ideal diode enable must be pulled high to deliver power to the boost converter.

Now the boost converter and the battery charger can be enabled or disabled using the corresponding control inputs. Switchover between the primary and the secondary power input happens automatically when the voltage at the primary power input drops below approximately 3 V. When the voltage rises above approximately 4.6 V, the boost converter is connected to the primary power input again.