Figure 3-14 shows the cell balancing circuit.
The design uses an internal
field-effect transistor (FET) to achieve a 100-mA balancing current. Assuming the
given condition: an initial CB voltage of 3.5 V, the final CB voltage is 3.3 V. To
achieve 100-mA balancing current while the CB voltage is 3.5 V, Rcb6 = Rcb5 = 15 Ω
is used.
The voltage across the
Rcb5 also provides bias voltage to the external cell balancing NPN transistor. The
Rcbe value can be determined based on the CB voltage and desired external cell
balancing current. Rb needs to meet two conditions:
- Condition 1: NPN transistor work
in the saturation region for a small heat dissipation area: ic
< Coefficient × hfe × ib. hfe is the DC current
transfer static ratio of the NPN transistor. The ic-hfe curve is found in the
NPN transistor data sheet. While the ic equals the desired external cell
balancing current, the corresponding maximum hfe in the whole temperature range
can be used to meet condition 1. The coefficient is usually set to 2 to keep the
NPN transistor in saturation region by a safe margin.
- Condition 2: UBE
> UBE(on). UBE(on) is the base-emitter turn-on voltage.
UBE(on) must be smaller than the voltage across the Rcb5 and as small as
possible to enable an easy selection of Rb.
This design uses 300 Ω for Rb,
which can support an external cell balancing current as large as 600
mA.