8.2.1.10.8 Efficiency Calculation Example
Operating conditions are:
Equation 44. VIN = 12 V
Equation 45. fSW = 2 MHz
Equation 46. VOUT = 3.3 V
Equation 47. VD1 = 0.5 V
Equation 48. IOUT = 2 A
Equation 49. RDCR = 20 mΩ
Internal Power Losses are:
Equation 50. PCOND = IOUT2 × RDSON x D= 22 × 0.15 Ω × 0.314 = 188 mW
Equation 51. PSW = (VIN x IOUT × ƒSW × tFALL) = (12 V × 2 A x 2 MHz × 10n s) = 480 mW
Equation 52. PQ = IQ × VIN = 2.4 mA × 12 V = 29 mW
Equation 53. PBOOST = IBOOST × VBOOST = 8.2 mA x 4.5V = 37 mW
Equation 54. PINTERNAL = PCOND + PSW + PQ + PBOOST = 733 mW
Total power losses are:
Equation 55. PDIODE= VD1 × IOUT (1 – D) = 0.5 V × 2 × (1 – 0.314) = 686 mW
Equation 56. PIND= IOUT2 × RDCR = 22 × 20 mΩ = 80 mW
Equation 57. PLOSS = PINTERNAL + PDIODE + P IND = 1.499 W
The efficiency can now be estimated as:
Equation 58.
With this information we can estimate the junction temperature of the LMR12015/20.