SLVSHN0 September 2024 TPS548B23
ADVANCE INFORMATION
To calculate the value of the output inductor (LOUT), use Equation 9. The output capacitor filters the inductor-ripple current (IIND(ripple)). Therefore, selecting a high inductor-ripple current impacts the selection of the output capacitor because the output capacitor must have a ripple-current rating equal to or greater than the inductor-ripple current. On the other hand, larger ripple current increases output ripple voltage, but improves signal-to-noise ratio and helps to stabilize operation. Generally speaking, the inductance value must set the ripple current at approximately 15% to 40% of the maximum output current for a balanced performance.
For this design, the inductor-ripple current is set to 30% of 20A output current. With a 800klHz switching frequency, 16V as maximum VIN, and 3.3V as the output voltage, Based on these parmaters, Equation 9 calculates an inductance of 0.546μH . A nearest standard value of 0.55µH is chosen.
The inductor requires a low DCR to achieve good efficiency. The inductor also requires enough room above peak inductor current before saturation. The inductor current ripple is estimated using Equation 10. For this design, by tying the CFG1 pin to VCC, IOC(valley) is set to 21A, thus peak inductor current under maximum VIN is calculated as 22.98A with Equation 11.
The selected inductance is a Coilcraft XAL7070-551MEB. This has a saturation current rating of 43 A , RMS current rating of 29-A and a DCR of 1.6 mΩ max. This inductor was selected for its low DCR to get high efficiency.